What is laplacetransform e^{-3t}*sin(t) ?

The answer to laplacetransform e^{-3t}*sin(t) is 1/((s+3)^2+1)

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laplacetransform e^{-3t}*sin(t)

laplace transform

e^{- 3 t} \cdot sin (t)

\frac{1}{( s + 3 ) ^{2} + 1}

Solution steps

L {e^{- 3 t} sin (t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{- 3 t} sin (t) : f (t) = sin (t), a = - 3

= L {sin (t)} (s + 3)

L {sin (t)} : \frac{1}{s ^{2} + 1}

= \frac{1}{( s + 3 ) ^{2} + 1}

x \to 3 + lim (\frac{2}{x + 3})

F (x) = x^{4} - 8 x^{2} + 2

x \to 2 lim (n x + 2)

\frac{d}{d x} (sin (5) x^{5})

x \to 2 lim (x^{2} - 4)

What is laplacetransform e^{-3t}*sin(t) ?
The answer to laplacetransform e^{-3t}*sin(t) is 1/((s+3)^2+1)