What is the derivative of f(x)= 2/(2x+1) ?

The derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)

What is the first derivative of f(x)= 2/(2x+1) ?

The first derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)

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derivative of

f (x) = \frac{2}{2 x + 1}

- \frac{4}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{2 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 2 (- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2)

Simplify

2 (- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2) : - \frac{4}{( 2 x + 1 ) ^{2}}

= - \frac{4}{( 2 x + 1 ) ^{2}}

d er i v a t i v e \frac{2 z ^{3}}{3} - z

y y^{^{'}} - 21 e^{x} = 0

d er i v a t i v e (1 - t) (1 + t^{2})^{- 1}

\frac{\partial}{\partial y} (ln (x - 9 y))

a re a y = ∣ x - 9 ∣, y = \frac{x}{2}

What is the derivative of f(x)= 2/(2x+1) ?
The derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)
What is the first derivative of f(x)= 2/(2x+1) ?
The first derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)