What is the d/(dp)((400)/(p^2)) ?

The d/(dp)((400)/(p^2)) is -(800)/(p^3)

What is the first d/(dp)((400)/(p^2)) ?

The first d/(dp)((400)/(p^2)) is -(800)/(p^3)

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\frac{d}{d p} (\frac{400}{p ^{2}})

- \frac{800}{p ^{3}}

Solution steps

\frac{d}{d p} (\frac{400}{p ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 400 \frac{d}{d p} (\frac{1}{p ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 400 \frac{d}{d p} (p^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 400 (- 2 p^{- 2 - 1})

Simplify

400 (- 2 p^{- 2 - 1}) : - \frac{800}{p ^{3}}

= - \frac{800}{p ^{3}}

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What is the d/(dp)((400)/(p^2)) ?
The d/(dp)((400)/(p^2)) is -(800)/(p^3)
What is the first d/(dp)((400)/(p^2)) ?
The first d/(dp)((400)/(p^2)) is -(800)/(p^3)