What is the solution for y^'+0.121y=-3 ?

The solution for y^'+0.121y=-3 is y=(e^{-0.121t-c_{1}})/(0.121)-3/(0.121)

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y^'+0.121y=-3

y^{^{'}} + 0.121 y = - 3

y = \frac{e ^{- 0.121 t - c_{1}}}{0.121} - \frac{3}{0.121}

Solution steps

y^{'} (t) + 0.121 y = - 3

Solve separable ODE:

y = \frac{e ^{- 0.121 t - c_{1}}}{0.121} - \frac{3}{0.121}

y = \frac{e ^{- 0.121 t - c_{1}}}{0.121} - \frac{3}{0.121}

y^{^{'}} = \frac{( 3 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2} )}{x ^{6} y}

\frac{\partial}{\partial x} (\frac{1}{x + c t})

\int_{l n (2)}^{3} (5 e^{x}) d x

x \to 2 lim (x - 3)

\int_{0}^{1} (x^{2} - x^{3}) d x

What is the solution for y^'+0.121y=-3 ?
The solution for y^'+0.121y=-3 is y=(e^{-0.121t-c_{1}})/(0.121)-3/(0.121)