What is the derivative of ln(ln(9s)) ?

The derivative of ln(ln(9s)) is 1/(sln(9s))

What is the first derivative of ln(ln(9s)) ?

The first derivative of ln(ln(9s)) is 1/(sln(9s))

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derivative of

ln (ln (9 s))

\frac{1}{s ln ( 9 s )}

Solution steps

\frac{d}{d s} (ln (ln (9 s)))

Apply the chain rule:

\frac{1}{ln ( 9 s )} \frac{d}{d s} (ln (9 s))

= \frac{1}{ln ( 9 s )} \frac{d}{d s} (ln (9 s))

\frac{d}{d s} (ln (9 s)) = \frac{1}{s}

= \frac{1}{ln ( 9 s )} \cdot \frac{1}{s}

Simplify

\frac{1}{ln ( 9 s )} \cdot \frac{1}{s} : \frac{1}{s ln ( 9 s )}

= \frac{1}{s ln ( 9 s )}

- t^{2} + 2 t + 4

\frac{d y}{d x} = \frac{1}{1 + x ^{2}}

\frac{5 s}{s ^{2} + 4 s + 5}

(2 y + 2 t - 9) d t + (4 y + 2 t - 1) d y = 0

\int (3 - x)^{2} d x

What is the derivative of ln(ln(9s)) ?
The derivative of ln(ln(9s)) is 1/(sln(9s))
What is the first derivative of ln(ln(9s)) ?
The first derivative of ln(ln(9s)) is 1/(sln(9s))