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Beliebt Rechnen >

derivative of sec^2(xdx)

Lösung

\frac{d}{d x} (sec^{2} (x) d x)

Lösung

d (2 x sec^{2} (x) tan (x) + sec^{2} (x))

Schritte zur Lösung

\frac{d}{d x} (sec^{2} (x) d x)

Behandle

d

als Konstante

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (sec^{2} (x) x)

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec^{2} (x), g = x

= d (\frac{d}{d x} (sec^{2} (x)) x + \frac{d x}{d x} sec^{2} (x))

\frac{d}{d x} (sec^{2} (x)) = 2 sec^{2} (x) tan (x)

\frac{d x}{d x} = 1

= d (2 sec^{2} (x) tan (x) x + 1 \cdot sec^{2} (x))

Vereinfache

= d (2 x sec^{2} (x) tan (x) + sec^{2} (x))

Graph

Beliebte Beispiele

(6-10y+e^{-5x})dx-2dy=0

(6 - 10 y + e^{- 5 x}) d x - 2 d y = 0

tangent y=sec(x),(pi/3 ,2)

t an g e n t y = sec (x), (\frac{π}{3}, 2)

y^'=(1-2x)y^2,y(0)=-1/6

y^{^{'}} = (1 - 2 x) y^{2}, y (0) = - \frac{1}{6}

derivative of 3sin(x+2cos(x))

\frac{d}{d x} (3 sin (x) + 2 cos (x))

y^{''}-2y^'+y=te^t

y^{^{''}} - 2 y^{^{'}} + y = t e^{t}