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Beliebt Rechnen >

y^{''}+20y^'+500y=0

Lösung

y^{^{''}} + 20 y^{^{'}} + 500 y = 0

Lösung

y = e^{- 10 t} (c_{1} cos (20 t) + c_{2} sin (20 t))

Schritte zur Lösung

y^{''} (t) + 20 y^{'} (t) + 500 y = 0

Solve linear ODE:

y = e^{- 10 t} (c_{1} cos (20 t) + c_{2} sin (20 t))

y = e^{- 10 t} (c_{1} cos (20 t) + c_{2} sin (20 t))

Graph

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