(dy)/(dx)=(x+y+9)^2

Lösung

\frac{d y}{d x} = (x + y + 9)^{2}

y = tan (x + c_{1}) - x - 9

Schritte zur Lösung

\frac{d y}{d x} = (x + y + 9)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x - 9

y = tan (x + c_{1}) - x - 9

\int_{- 2}^{3} \frac{25}{x ^{4}} d x

\frac{d}{d x} (\frac{1}{2 3 x ^{2}})

\int_{0}^{\infty} sin (4 x) d x

\int \frac{- 9}{x ^{2} + 16} d x

\frac{d ^{2}}{d x ^{2}} ((3 x^{2} + 6 x) sin (x))