limit as x approaches+0 of ln(x^2)

解答

x \to + 0 lim (ln (x^{2}))

不存在

求解步骤

x \to 0 lim (ln (x^{2}))

若

x \to a^{-} lim f (x) \neq = x \to a^{+} lim f (x)

则极限不存在

x \to 0 + lim (ln (x^{2})) = - \infty

x \to 0 - lim (ln (x^{2})) =

不存在

= 不存在

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