derivative 1/(2sqrt(r))+1/(4r^{3/4)}

Lösung

ableitung von

\frac{1}{2 r} + \frac{1}{4 r ^{\frac{3}{4}}}

- \frac{1}{4 r ^{\frac{3}{2}}} - \frac{3}{16 r ^{\frac{7}{4}}}

Schritte zur Lösung

\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{4 r ^{\frac{3}{4}}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (\frac{1}{2 r}) + \frac{d}{d r} (\frac{1}{4 r ^{\frac{3}{4}}})

\frac{d}{d r} (\frac{1}{2 r}) = - \frac{1}{4 r ^{\frac{3}{2}}}

\frac{d}{d r} (\frac{1}{4 r ^{\frac{3}{4}}}) = - \frac{3}{16 r ^{\frac{7}{4}}}

= - \frac{1}{4 r ^{\frac{3}{2}}} - \frac{3}{16 r ^{\frac{7}{4}}}

d er i v a t i v e arctan (\frac{x}{2})

\int x^{5} x^{6} + 8 d x

a re a 1, cos^{2} (x), [0, π]

x \to 0 lim ((tan (9 x))^{x})

\frac{d}{d x} (4 lo g_{3} (x^{2} - 1))