integral of 1/(3x)+cos(2x)-5x^2

解答

\int \frac{1}{3 x} + cos (2 x) - 5 x^{2} d x

\frac{1}{3} ln ∣ x ∣ + \frac{1}{2} sin (2 x) - \frac{5 x ^{3}}{3} + C

求解步骤

\int \frac{1}{3 x} + cos (2 x) - 5 x^{2} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{3 x} d x + \int cos (2 x) d x - \int 5 x^{2} d x

\int \frac{1}{3 x} d x = \frac{1}{3} ln ∣ x ∣

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

= \frac{1}{3} ln ∣ x ∣ + \frac{1}{2} sin (2 x) - \frac{5 x ^{3}}{3}

解答补常数

= \frac{1}{3} ln ∣ x ∣ + \frac{1}{2} sin (2 x) - \frac{5 x ^{3}}{3} + C

\frac{d}{d θ} (cot^{2} (sin (θ)))

\frac{d}{d t} (e^{4 t} cos (t))

\frac{d}{d x} (\frac{7 x - 4}{- 3 x + 3})

d er i v a t i v e - 6

x \to 5 lim (2 x - 5)