What is the integral of-1/(2sqrt(x)) ?

The integral of-1/(2sqrt(x)) is -sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of-1/(2sqrt(x))

\int - \frac{1}{2 x} d x

- x + C

Solution steps

\int - \frac{1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int \frac{1}{x} d x

Apply the Power Rule

= - \frac{1}{2} \cdot 2 x^{\frac{1}{2}}

Simplify

- \frac{1}{2} \cdot 2 x^{\frac{1}{2}} : - x

= - x

Add a constant to the solution

= - x + C

t an g e n t \frac{6 x}{4 - x ^{2}}, at x = 0

\frac{d}{d x} (4 7 x^{2} + 9)

\frac{\partial}{\partial x} (4 ln (\frac{2 x y}{7 z}))

d er i v a t i v e h (w) = \frac{4 w ^{5} - w}{w}

\int x e^{1 - x} d x

What is the integral of-1/(2sqrt(x)) ?
The integral of-1/(2sqrt(x)) is -sqrt(x)+C