limit as θ approaches 0 of (sin(θ))/(sin(2θ))

Lösung

θ \to 0 lim (\frac{sin ( θ )}{sin ( 2 θ )})

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

θ \to 0 lim (\frac{sin ( θ )}{sin ( 2 θ )})

Wende das L'Hopital Theorem an

= θ \to 0 lim (\frac{cos ( θ )}{cos ( 2 θ ) \cdot 2})

Setze den Wert

θ = 0

ein

= \frac{cos ( 0 )}{cos ( 2 \cdot 0 ) \cdot 2}

Vereinfache

\frac{cos ( 0 )}{cos ( 2 \cdot 0 ) \cdot 2} : \frac{1}{2}

= \frac{1}{2}

\frac{\partial}{\partial x} (5 x cos (x) cos (y))

n = 1 \sum \infty 0. 7^{n}

d er i v a t i v e e^{\frac{z}{z - 1}}

d er i v a t i v e y = x - cos^{2} (x)

\frac{\partial}{\partial x} (\frac{x}{x + \frac{y}{x}})