y^{''}+y= 3/2 sin(x)

解答

y^{^{''}} + y = \frac{3}{2} sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{4}

求解步骤

y^{''} (x) + y = \frac{3}{2} sin (x)

求解线性方程:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{4}

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{4}

\int x + 1 x d x

\int \frac{sin ( 2 x )}{18 + cos ^{2} ( x )} d x

y^{^{'}} + 3 y + 5 = 0

\int e^{x - 3} d x

\frac{d}{d x} (sin^{4} (2 x co) s^{4} 3 x)