y^'-4y^2=2ty^2

Lösung

y^{^{'}} - 4 y^{2} = 2 t y^{2}

y = - \frac{1}{t ^{2} + 4 t + c _{1}}

Schritte zur Lösung

y^{'} (t) - 4 y^{2} = 2 t y^{2}

Solve separable ODE:

y = - \frac{1}{t ^{2} + 4 t + c _{1}}

y = - \frac{1}{t ^{2} + 4 t + c _{1}}

2 x^{3} y^{^{'}} = y (2 x^{2} - y^{2})

t an g e n t f (x) = 12 (x - \frac{1}{x})^{2}, at x = 2

\int \frac{( e ^{x} + e ^{- x} )}{2} d x

x \to 0 lim (\frac{2 x}{x})

x \to - 4 - lim (\frac{2}{x ^{2} - 16})