What is (\partial)/(\partial x)(81x^8y^8-64x^7y^7) ?

The answer to (\partial)/(\partial x)(81x^8y^8-64x^7y^7) is 648y^8x^7-448y^7x^6

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(\partial)/(\partial x)(81x^8y^8-64x^7y^7)

\frac{\partial}{\partial x} (81 x^{8} y^{8} - 64 x^{7} y^{7})

648 y^{8} x^{7} - 448 y^{7} x^{6}

Solution steps

\frac{\partial}{\partial x} (81 x^{8} y^{8} - 64 x^{7} y^{7})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (81 x^{8} y^{8}) - \frac{\partial}{\partial x} (64 x^{7} y^{7})

\frac{\partial}{\partial x} (81 x^{8} y^{8}) = 648 y^{8} x^{7}

\frac{\partial}{\partial x} (64 x^{7} y^{7}) = 448 y^{7} x^{6}

= 648 y^{8} x^{7} - 448 y^{7} x^{6}

\int_{0}^{\frac{π}{2}} x cos (x^{2}) d x

(5 - 5 x^{3})^{3} + \frac{1}{5 - 5 x ^{3}}

\int xx d x

\frac{d}{d x} (\frac{2}{x - 6})

\frac{d}{d x} (6 x - 2)

What is (\partial)/(\partial x)(81x^8y^8-64x^7y^7) ?
The answer to (\partial)/(\partial x)(81x^8y^8-64x^7y^7) is 648y^8x^7-448y^7x^6