What is the derivative of 2x^2-7x+k ?

The derivative of 2x^2-7x+k is 4x-7

What is the first derivative of 2x^2-7x+k ?

The first derivative of 2x^2-7x+k is 4x-7

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derivative of

2 x^{2} - 7 x + k

4 x - 7

Solution steps

\frac{d}{d x} (2 x^{2} - 7 x + k)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (7 x) + \frac{d k}{d x}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7 x) = 7

\frac{d k}{d x} = 0

= 4 x - 7 + 0

Simplify

= 4 x - 7

\int (6 x) d x

y = - 3 x^{3} - 3 x^{2} - x + 3, (- 1, 4)

y^{^{''}} + 2 y^{^{'}} + 2 = cos (t), y (0) = 0, y^{^{'}} (0) = 0

y = - 3 x \frac{d y}{d x}

(v^{- 3} + 3 v^{- 2})^{3}

What is the derivative of 2x^2-7x+k ?
The derivative of 2x^2-7x+k is 4x-7
What is the first derivative of 2x^2-7x+k ?
The first derivative of 2x^2-7x+k is 4x-7