derivative 45+22sin((2pi)/(52)(t-10))

Lösung

ableitung von

45 + 22 sin (\frac{2 π}{52} (t - 10))

\frac{11 π}{13} cos (\frac{π ( t - 10 )}{26})

Schritte zur Lösung

\frac{d}{d t} (45 + 22 sin (\frac{2 π}{52} (t - 10)))

Vereinfache

45 + 22 sin (\frac{2 π}{52} (t - 10)) : 45 + 22 sin (\frac{π ( t - 10 )}{26})

= \frac{d}{d t} (45 + 22 sin (\frac{π ( t - 10 )}{26}))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (45) + \frac{d}{d t} (22 sin (\frac{π ( t - 10 )}{26}))

\frac{d}{d t} (45) = 0

\frac{d}{d t} (22 sin (\frac{π ( t - 10 )}{26})) = \frac{11 π}{13} cos (\frac{π ( t - 10 )}{26})

= 0 + \frac{11 π}{13} cos (\frac{π ( t - 10 )}{26})

Vereinfache

= \frac{11 π}{13} cos (\frac{π ( t - 10 )}{26})

12 y^{^{''}} - 5 y^{^{'}} - 3 y = 0

\int \frac{1}{25 e ^{- 5 x} + e ^{5 x}} d x

d er i v a t i v e f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 4)

\int_{0}^{2} (x^{3} - 1)^{2} d x

y^{^{'}} = y - 2 x - 1