derivative f(x)=2x^2+3x-2

Lösung

ableitung von

f (x) = 2 x^{2} + 3 x - 2

4 x + 3

Schritte zur Lösung

\frac{d}{d x} (2 x^{2} + 3 x - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 4 x + 3 - 0

Vereinfache

= 4 x + 3

s l o p e y = 3 x^{2} + 2 x + 9

n = 1 \sum \infty (- 1)^{n} n

n \to \infty lim ((n!)^{2})

\int y cos (yz) d z

d er i v a t i v e - 7 h x^{2} - 5 h x - 3 h^{2} x + 5 h^{2} + 4 h^{3}