What is the first derivative of 2x-8 ?

The first derivative of 2x-8 is 2

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derivative of 2x-8

\frac{d}{d x} (2 x - 8)

2

Solution steps

\frac{d}{d x} (2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 - 0

Simplify

= 2

\frac{d ^{2}}{d x ^{2}} (9 cos (2 x))

\frac{d}{d x} (2 sin (3 x) + 1)

x \to 0 lim (\frac{e ^{x^{2}} - 1}{x})

\frac{d}{d x} (34 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

y^{^{'}} - 8 y 2 e - 5 x = 0, y (0) = 7