y^'+9tan(9x)=7cos(9x)

Lösung

y^{^{'}} + 9 tan (9 x) = 7 cos (9 x)

y = \frac{7}{9} sin (9 x) + ln (cos (9 x)) + c_{1}

Schritte zur Lösung

y^{'} (x) + 9 tan (9 x) = 7 cos (9 x)

Isoliere

y^{'} (x) : y^{'} (x) = 7 cos (9 x) - 9 tan (9 x)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 7 cos (9 x) - 9 tan (9 x) d x

\int 7 cos (9 x) - 9 tan (9 x) d x = \frac{7}{9} sin (9 x) + ln (cos (9 x)) + c_{1}

y = \frac{7}{9} sin (9 x) + ln (cos (9 x)) + c_{1}

\frac{d}{d x} (- x cos (x) + sin (x))

\frac{d}{d x} (\frac{1}{2} x^{4} - 2 x^{2})

x \to 3 lim (\frac{x ^{3} - 9}{x - 3})

d er i v a t i v e (8 (2 x)^{4} + 5)^{3}

\frac{\partial}{\partial x} ((x^{p} + y^{p})^{\frac{1}{p}})