What is the derivative of f(x)=(2x^3+2)(x^4-3x) ?

The derivative of f(x)=(2x^3+2)(x^4-3x) is 14x^6-16x^3-6

What is the first derivative of f(x)=(2x^3+2)(x^4-3x) ?

The first derivative of f(x)=(2x^3+2)(x^4-3x) is 14x^6-16x^3-6

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derivative of

f (x) = (2 x^{3} + 2) (x^{4} - 3 x)

14 x^{6} - 16 x^{3} - 6

Solution steps

\frac{d}{d x} ((2 x^{3} + 2) (x^{4} - 3 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x^{3} + 2, g = x^{4} - 3 x

= \frac{d}{d x} (2 x^{3} + 2) (x^{4} - 3 x) + \frac{d}{d x} (x^{4} - 3 x) (2 x^{3} + 2)

\frac{d}{d x} (2 x^{3} + 2) = 6 x^{2}

\frac{d}{d x} (x^{4} - 3 x) = 4 x^{3} - 3

= 6 x^{2} (x^{4} - 3 x) + (4 x^{3} - 3) (2 x^{3} + 2)

Simplify

6 x^{2} (x^{4} - 3 x) + (4 x^{3} - 3) (2 x^{3} + 2) : 14 x^{6} - 16 x^{3} - 6

= 14 x^{6} - 16 x^{3} - 6

\int_{0}^{2} 3^{- x} d x

y^{^{''}} - 2 y^{^{'}} + 10 y = e^{x} cos (3 x)

\int sin (u^{2}) d u

\int \frac{37}{x ^{3} - 27} d x

\frac{\partial}{\partial y} (\frac{2 y}{x ^{2} + y ^{2}})

What is the derivative of f(x)=(2x^3+2)(x^4-3x) ?
The derivative of f(x)=(2x^3+2)(x^4-3x) is 14x^6-16x^3-6
What is the first derivative of f(x)=(2x^3+2)(x^4-3x) ?
The first derivative of f(x)=(2x^3+2)(x^4-3x) is 14x^6-16x^3-6