What is (\partial)/(\partial y)(4y^3cos(2x)) ?

The answer to (\partial)/(\partial y)(4y^3cos(2x)) is 12y^2cos(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(4y^3cos(2x))

\frac{\partial}{\partial y} (4 y^{3} cos (2 x))

12 y^{2} cos (2 x)

Solution steps

\frac{\partial}{\partial y} (4 y^{3} cos (2 x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 cos (2 x) \frac{\partial}{\partial y} (y^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 cos (2 x) \cdot 3 y^{3 - 1}

Simplify

= 12 y^{2} cos (2 x)

\int \frac{1}{x 1 + x} d x

\int \frac{- 1}{2 ( x + 1 )} d x

\int x^{4} ln (3 x) d x

(x^{2} + 1)^{3} (x^{2} + 2)^{6}

\int_{- l n (4)}^{0} 33 e^{t} d t

What is (\partial)/(\partial y)(4y^3cos(2x)) ?
The answer to (\partial)/(\partial y)(4y^3cos(2x)) is 12y^2cos(2x)