3xy^'-2y=(x^3)/(y^2)

Lösung

3 x y^{^{'}} - 2 y = \frac{x ^{3}}{y ^{2}}

y = 3 x^{3} + c_{1} x^{2}

Schritte zur Lösung

3 x y^{'} (x) - 2 y = \frac{x ^{3}}{y ^{2}}

Solve Bernoulli ODE:

y = 3 x^{3} + c_{1} x^{2}

y = 3 x^{3} + c_{1} x^{2}

a re a x, 2 x, - x + 2

l a pl a ce t r an s f or m t e^{- 4 t} cos (5 t)

a re a - x^{4}, x^{2} - 2 x

\frac{d}{d x} (\frac{1 - 3 e ^{x}}{1 - 2 cos ( x )})

\frac{\partial}{\partial y} (e^{x y} + 2 x + 3 y)