derivative 2+\sqrt[5]{x}

Lösung

ableitung von

2 + 5 x

\frac{1}{5 x ^{\frac{4}{5}}}

Schritte zur Lösung

\frac{d}{d x} (2 + 5 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (5 x)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (5 x) = \frac{1}{5 x ^{\frac{4}{5}}}

= 0 + \frac{1}{5 x ^{\frac{4}{5}}}

Vereinfache

= \frac{1}{5 x ^{\frac{4}{5}}}

\frac{\partial}{\partial x} (\frac{q ( x , r , s , t ) x + r}{s x + t})

\frac{d}{d x} (x - \frac{2}{x})

t an g e n t f (x) = x^{3} - 6 x, (2, - 4)

\int_{- 1}^{3} (2 x^{2} + 1) d x

\frac{\partial}{\partial y} (ln (x^{3} + y^{4}))