integral from 0 to 1 of (4sqrt(x))-(4x)

解

\int_{0}^{1} (4 x) - (4 x) d x

\frac{2}{3}

十進法表記

0.66666 \dots

解答ステップ

\int_{0}^{1} 4 x - 4 x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x - \int_{0}^{1} 4 x d x

\int_{0}^{1} 4 x d x = \frac{8}{3}

\int_{0}^{1} 4 x d x = 2

= \frac{8}{3} - 2

簡素化

\frac{8}{3} - 2 : \frac{2}{3}

= \frac{2}{3}