integral of (4x+2)^2

Lösung

\int (4 x + 2)^{2} d x

\frac{16 x ^{3}}{3} + 8 x^{2} + 4 x + C

Schritte zur Lösung

\int (4 x + 2)^{2} d x

Multipliziere aus

(4 x + 2)^{2} : 16 x^{2} + 16 x + 4

= \int 16 x^{2} + 16 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 16 x^{2} d x + \int 16 x d x + \int 4 d x

\int 16 x^{2} d x = \frac{16 x ^{3}}{3}

\int 16 x d x = 8 x^{2}

\int 4 d x = 4 x

= \frac{16 x ^{3}}{3} + 8 x^{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= \frac{16 x ^{3}}{3} + 8 x^{2} + 4 x + C

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