x^{''}+2x^'+4x=0

Lösung

x^{^{''}} + 2 x^{^{'}} + 4 x = 0

x = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t))

Schritte zur Lösung

x^{''} (t) + 2 x^{'} (t) + 4 x = 0

Solve linear ODE:

x = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t))

x = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t))

\frac{d}{d z} (\frac{z + i}{z - i})

x \to - 1 lim (3 x^{2} - 2 x^{2} + 4)

l a pl a ce t r an s f or m e^{3} e^{t} (- sin (π t))

y^{^{'}} = y^{2} - 4

\int_{1}^{R} x^{- \frac{8}{5}} d x