(dy)/(dx)=e^{2-x}

Lösung

\frac{d y}{d x} = e^{2 - x}

y = - e^{2 - x} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = e^{2 - x}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = e^{2 - x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int e^{2 - x} d x

\int e^{2 - x} d x = - e^{2 - x} + c_{1}

y = - e^{2 - x} + c_{1}

x \to 2 lim (\frac{x}{[ ( x ^{2} ) - 4 ]})

(x + \frac{2}{y}) d y + y d x = 0

\int_{0}^{2} \frac{1}{x ^{3}} d x

\frac{\partial}{\partial x} (- 2 y + 2 x)

t an g e n t f (x) = (ln (x))^{2}, at x = 11