derivative of 1-x/2+(x^2/9)

解答

\frac{d}{d x} (1 - \frac{x}{2} + \frac{x ^{2}}{9})

\frac{2 x}{9} - \frac{1}{2}

求解步骤

\frac{d}{d x} (1 - \frac{x}{2} + \frac{x ^{2}}{9})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{x}{2}) + \frac{d}{d x} (\frac{x ^{2}}{9})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{x}{2}) = \frac{1}{2}

\frac{d}{d x} (\frac{x ^{2}}{9}) = \frac{2 x}{9}

= 0 - \frac{1}{2} + \frac{2 x}{9}

化简

= \frac{2 x}{9} - \frac{1}{2}

\frac{d}{d x} (x^{3} (x^{4} - 1))

t an g e n t f (x) = - 3 x^{3} - 2 x^{2} - 1, at - 1

in v erse l a pl a ce \frac{s + 3}{s + 1 ( s + 2 )}

\int - 2 sin^{2} (t) d t

\frac{\partial}{\partial x} (4374 x^{\frac{1}{3}} + 2 y)