面积-4x^2+9,x+7,0

解答

面积

- 4 x^{2} + 9, x + 7, 0

无解

求解步骤

要找到相交点，解

f_{i} (x) = f_{j} (x)

- 4 x^{2} + 9 = x + 7 : x = - \frac{1 + 33}{8}, x = \frac{33 - 1}{8}

- 4 x^{2} + 9 = 0 : x = \frac{3}{2}, x = - \frac{3}{2}

x + 7 = 0 : x = - 7

曲线没有界限

= 无解

d er i v a t i v e x^{9}

x y y^{^{'}} + 1 + x^{2} + y^{2} = 0

n = 0 \sum \infty arctan (n^{2})

x^{^{''}} = x^{^{'}}

t an g e n t f (x) = 2 x - 1, at x = 5