integral of ((2x+3))/((x+7)^3)

Lösung

\int \frac{( 2 x + 3 )}{( x + 7 ) ^{3}} d x

- \frac{2}{x + 7} + \frac{7}{( x + 7 ) ^{2}} - \frac{3}{2 ( x + 7 ) ^{2}} + C

Schritte zur Lösung

\int \frac{2 x + 3}{( x + 7 ) ^{3}} d x

Multipliziere aus

\frac{2 x + 3}{( x + 7 ) ^{3}} : \frac{2 x}{( x + 7 ) ^{3}} + \frac{3}{( x + 7 ) ^{3}}

= \int \frac{2 x}{( x + 7 ) ^{3}} + \frac{3}{( x + 7 ) ^{3}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x}{( x + 7 ) ^{3}} d x + \int \frac{3}{( x + 7 ) ^{3}} d x

\int \frac{2 x}{( x + 7 ) ^{3}} d x = - \frac{2}{x + 7} + \frac{7}{( x + 7 ) ^{2}}

\int \frac{3}{( x + 7 ) ^{3}} d x = - \frac{3}{2 ( x + 7 ) ^{2}}

= - \frac{2}{x + 7} + \frac{7}{( x + 7 ) ^{2}} - \frac{3}{2 ( x + 7 ) ^{2}}

Füge eine Konstante zur Lösung hinzu

= - \frac{2}{x + 7} + \frac{7}{( x + 7 ) ^{2}} - \frac{3}{2 ( x + 7 ) ^{2}} + C

n = 1 \sum \infty 3 (\frac{1}{5})^{n - 1}

d er i v a t i v e f (x) = e^{2 x} - 1

n = 1 \sum \infty - n

x \to 0 lim (\frac{sin ( 3 x ^{2} )}{ln ( x ^{2} + 1 )})

\frac{d}{d x} (\frac{x}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}})