integral from-1 to 1 of 7x^2-4x-3

Lösung

\int_{- 1}^{1} 7 x^{2} - 4 x - 3 d x

- \frac{4}{3}

Dezimale

- 1.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} 7 x^{2} - 4 x - 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 7 x^{2} d x - \int_{- 1}^{1} 4 x d x - \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} 7 x^{2} d x = \frac{14}{3}

\int_{- 1}^{1} 4 x d x = 0

\int_{- 1}^{1} 3 d x = 6

= \frac{14}{3} - 0 - 6

Vereinfache

\frac{14}{3} - 0 - 6 : - \frac{4}{3}

= - \frac{4}{3}

t \frac{d y}{d t} + 5 y = t^{3}

\int \frac{1}{8 + 2 x - x ^{2}} d x

x \to \infty lim (8 x^{2})

t an g e n t f (x) = 5 tan (x), at x = 1.57

x \to 0 lim (\frac{sin ( 3 x )}{sin ( 6 x )})