What is area y=x^2,y=4-x^2 ?

The answer to area y=x^2,y=4-x^2 is -(8sqrt(2))/3+8sqrt(2)

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area y=x^2,y=4-x^2

area

y = x^{2}, y = 4 - x^{2}

- \frac{8 2}{3} + 82

Decimal

7.54247 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} - (4 - x^{2}) d x

Solve

\int_{- 2}^{2} x^{2} - (4 - x^{2}) d x : - \frac{8 2}{3} + 82

The area is:

= - \frac{8 2}{3} + 82

\frac{d}{d x} (\frac{x}{5 + x})

x \to 0 lim (\frac{2 - 2 cos ( x )}{e ^{x} - x - 1})

\int \frac{( ln ( x ) )}{x ^{2}} d x

\frac{\partial}{\partial x} (x^{8} y^{6} - x^{7} y^{5})

x \to \infty lim (7^{- x})

What is area y=x^2,y=4-x^2 ?
The answer to area y=x^2,y=4-x^2 is -(8sqrt(2))/3+8sqrt(2)