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人気のある微分積分 >

limit as x approaches infinity of (4^{x+1}+2^x)/(4^x)

解

x \to \infty lim (\frac{4 ^{x + 1} + 2 ^{x}}{4 ^{x}})

解

4

解答ステップ

x \to \infty lim (\frac{4 ^{x + 1} + 2 ^{x}}{4 ^{x}})

4^{x + 1}

を

4^{x + 1} + 2^{x} : 4^{x + 1} (1 + \frac{2 ^{x}}{4 ^{x + 1}})

からくくり出す

= x \to \infty lim (\frac{4 ^{x + 1} ( 1 + \frac{2 ^{x}}{4 ^{x + 1}} )}{4 ^{x}})

簡素化

\frac{4 ^{x + 1} ( 1 + \frac{2 ^{x}}{4 ^{x + 1}} )}{4 ^{x}} : 4 (\frac{2 ^{x}}{4 ^{x + 1}} + 1)

= x \to \infty lim (4 (\frac{2 ^{x}}{4 ^{x + 1}} + 1))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 4 \cdot x \to \infty lim (\frac{2 ^{x}}{4 ^{x + 1}} + 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

不定形式の場合を除く

= 4 (x \to \infty lim (\frac{2 ^{x}}{4 ^{x + 1}}) + x \to \infty lim (1))

x \to \infty lim (\frac{2 ^{x}}{4 ^{x + 1}}) = 0

x \to \infty lim (1) = 1

= 4 (0 + 1)

簡素化

= 4

グラフ

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