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Popular Calculus >

y^'=(x-1)e^x

Solution

y^{^{'}} = (x - 1) e^{x}

Solution

y = e^{x} x - 2 e^{x} + c_{1}

Solution steps

y^{'} (x) = (x - 1) e^{x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (x - 1) e^{x} d x

\int (x - 1) e^{x} d x = e^{x} x - 2 e^{x} + c_{1}

y = e^{x} x - 2 e^{x} + c_{1}

Graph

Popular Examples

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d er i v a t i v e \frac{0.3 ( 9 ^{x} )}{x ^{3}}

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\int (cos (x) + \frac{1}{2} x) d x

(dy}{dx}-y=\frac{e^x)/y

\frac{d y}{d x} - y = \frac{e ^{x}}{y}

(\partial)/(\partial x)((x^2)^{-1/2})

\frac{\partial}{\partial x} ((x^{2})^{- \frac{1}{2}})

derivative of u(x)=3x^2-x+6

d er i v a t i v e u (x) = 3 x^{2} - x + 6

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x-1)e^x ?
The solution for y^'=(x-1)e^x is y=e^xx-2e^x+c_{1}