(\partial)/(\partial x)(x^2+zsin(xyz))

解答

\frac{\partial}{\partial x} (x^{2} + z sin (x yz))

2 x + z^{2} y cos (zy x)

求解步骤

\frac{\partial}{\partial x} (x^{2} + z sin (x yz))

将

z, y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (z sin (x yz))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (z sin (x yz)) = z^{2} y cos (zy x)

= 2 x + z^{2} y cos (zy x)

\int \frac{( 1 - u ^{2} - u - u ^{3} )}{1 + u ^{2}} d u

d er i v a t i v e x^{2} - 3

\frac{d}{d z} (ln (\frac{b ^{2} - z ^{2}}{b ^{2} + z ^{2}}))

y^{^{''}} + 9 y = 4 csc^{2} (3 t)

\int 6 - 4 x - 4 x^{2} d x