d/(dt)(acos(wt)+bsin(wt))

Lösung

\frac{d}{d t} (a cos (wt) + b sin (wt))

- a w sin (wt) + b cos (wt) w

Schritte zur Lösung

\frac{d}{d t} (a cos (wt) + b sin (wt))

Behandle

a, b, w

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a cos (wt)) + \frac{d}{d t} (b sin (wt))

\frac{d}{d t} (a cos (wt)) = - a w sin (wt)

\frac{d}{d t} (b sin (wt)) = b cos (wt) w

= - a w sin (wt) + b cos (wt) w

\int (e^{5 x}) (cos (- 2 x)) d x

\int \frac{2 x + 1}{( x - 1 ) ( x + 3 )} d x

\frac{d}{d x} (\frac{x ^{2} - x + 5}{4 x - 1})

\frac{\partial}{\partial y} (e^{- 2 y} cos (x))

\frac{d}{d x} ((x - 1) (x^{2} - 8 x + 7))