(\partial)/(\partial y)(x^2y^2-xy+2)

Lösung

\frac{\partial}{\partial y} (x^{2} y^{2} - x y + 2)

2 x^{2} y - x

Schritte zur Lösung

\frac{\partial}{\partial y} (x^{2} y^{2} - x y + 2)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2} y^{2}) - \frac{\partial}{\partial y} (x y) + \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (x^{2} y^{2}) = 2 x^{2} y

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (2) = 0

= 2 x^{2} y - x + 0

Vereinfache

= 2 x^{2} y - x

\int \frac{x ^{2}}{2 x ^{2} - 9} d x

x \to - 1 lim (7 x + 2)

\int_{- 6}^{8} \frac{x}{2} + 8 d x

\int x^{5} 5 + x^{6} d x

\int \frac{x ^{3} - 6 x + 8}{x ^{2}} d x