d/(dy)(3cos(3x)(x-y)+sin(3x))

Lösung

\frac{d}{d y} (3 cos (3 x) (x - y) + sin (3 x))

- 3 cos (3 x)

Schritte zur Lösung

\frac{d}{d y} (3 cos (3 x) (x - y) + sin (3 x))

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (3 cos (3 x) (x - y)) + \frac{d}{d y} (sin (3 x))

\frac{d}{d y} (3 cos (3 x) (x - y)) = - 3 cos (3 x)

\frac{d}{d y} (sin (3 x)) = 0

= - 3 cos (3 x) + 0

Vereinfache

= - 3 cos (3 x)

n = 1 \sum \infty \frac{n ^{3}}{n ^{3}}

x \to 0 lim (x csc (3 x))

\frac{d}{d x} (ln (4) x^{2} + 3 x + 3)

\int (6 sin (x) + 3 sinh (x)) d x

\int \frac{2 x + 1}{x ^{2} + 1} d x