y^{''}-3y^'+2y=0,y(-1)=0,y^'(-1)=1

Lösung

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (- 1) = 0, y^{^{'}} (- 1) = 1

y = e^{2 t + 2} - e^{1 + t}

Schritte zur Lösung

y^{''} (t) - 3 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = e^{2 t + 2} - e^{1 + t}

y = e^{2 t + 2} - e^{1 + t}

\int \frac{3 x + 5}{x ( 2 x - 1 )} d x

d er i v a t i v e t^{3} e^{t} t

n \to \infty lim (c^{n})

y^{^{''}} + y^{^{'}} - 2 y = 0, y (0) = 1, y^{^{'}} (0) = 1

(3 cos (t))^{^{'}}