What is laplacetransform 8cos(t) ?

The answer to laplacetransform 8cos(t) is (8s)/(s^2+1)

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laplacetransform 8cos(t)

laplace transform

8 cos (t)

\frac{8 s}{s ^{2} + 1}

Solution steps

L {8 cos (t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 8 L {cos (t)}

L {cos (t)} : \frac{s}{s ^{2} + 1}

= 8 \cdot \frac{s}{s ^{2} + 1}

Refine

8 \frac{s}{s ^{2} + 1} : \frac{8 s}{s ^{2} + 1}

= \frac{8 s}{s ^{2} + 1}

y^{^{'}} + 2 y = 3 e^{2 x}

\int_{0}^{4} 2 π (x) (4 x - x^{2}) d x

\frac{d}{d x} (\frac{1}{x ^{- 5}})

2 \times 2 + 6 \times 1/22 \times 2

\frac{\partial}{\partial x} (y^{- 2} (4 y + 9 x^{2}))

What is laplacetransform 8cos(t) ?
The answer to laplacetransform 8cos(t) is (8s)/(s^2+1)