limit as x approaches 5-of (x+1)/(x-5)

Lösung

x \to 5 - lim (\frac{x + 1}{x - 5})

- \infty

Schritte zur Lösung

x \to 5 - lim (\frac{x + 1}{x - 5})

\frac{x + 1}{x - 5} = (x + 1) \frac{1}{x - 5}

= x \to 5 - lim ((x + 1) \frac{1}{x - 5})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

mit Einschränkung des unbestimmten Ausdrucks

= x \to 5 - lim (x + 1) \cdot x \to 5 - lim (\frac{1}{x - 5})

x \to 5 - lim (x + 1) = 6

x \to 5 - lim (\frac{1}{x - 5}) = - \infty

= 6 (- \infty)

Wende die Unendlichkeitseigenschaft an:

c \cdot (- \infty) = - \infty

= - \infty

f (x) = - cos (x)

\frac{d}{d x} (x (2 x + 1)^{3})

t an g e n t f (x) = (4 x^{2} - 3 x)^{2}, at x = 1

\int \frac{x ^{2} + 20 x - 4}{x ^{3} - 4 x} d x

\frac{\partial}{\partial z} (x y^{2} e^{- x z})