What is the tangent of f(x)= 7/x ,\at x=2 ?

The tangent of f(x)= 7/x ,\at x=2 is y=-7/4 x+7

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tangent of f(x)= 7/x ,\at x=2

tangent of

f (x) = \frac{7}{x}, at x = 2

y = - \frac{7}{4} x + 7

Solution steps

Find the tangent point:

(2, \frac{7}{2})

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{x ^{2}}

Compute the slope of

f (x) = \frac{7}{x}

x = 2 : m = - \frac{7}{4}

Find the line with slope m=

- \frac{7}{4}

and passing through

(2, \frac{7}{2}) : y = - \frac{7}{4} x + 7

y = - \frac{7}{4} x + 7

\int_{1}^{18} \frac{3}{z} d z

- x + 7 x^{2} - 15 x

y^{^{'}} = 7 y^{2} + x y^{2}, y (0) = 1

\int \frac{x ^{2} - 6 x + 9}{x ^{2} - 6 x + 18} d x

\int \frac{1}{x ^{3} + 27} d x

What is the tangent of f(x)= 7/x ,\at x=2 ?
The tangent of f(x)= 7/x ,\at x=2 is y=-7/4 x+7