d/(dy)(sqrt(y^2-1))

解答

\frac{d}{d y} (y^{2} - 1)

\frac{y}{y ^{2} - 1}

求解步骤

\frac{d}{d y} (y^{2} - 1)

使用连锁律:

\frac{1}{2 y ^{2} - 1} \frac{d}{d y} (y^{2} - 1)

= \frac{1}{2 y ^{2} - 1} \frac{d}{d y} (y^{2} - 1)

\frac{d}{d y} (y^{2} - 1) = 2 y

= \frac{1}{2 y ^{2} - 1} \cdot 2 y

化简

\frac{1}{2 y ^{2} - 1} \cdot 2 y : \frac{y}{y ^{2} - 1}

= \frac{y}{y ^{2} - 1}

\int \frac{1}{x ^{2} x ^{2} - 13} d x

\frac{d y}{d x} = 14 x e^{6} x (36 + y^{2})

\int 9 sin^{6} (x) d x

y^{^{'}} + y^{3} x + 9 y = 0

\int x^{5} + 8 x^{- 3} + 2 d x