integral from-3 to-1 of (x+2)^{99}

Lösung

\int_{- 3}^{- 1} (x + 2)^{99} d x

0

Schritte zur Lösung

\int_{- 3}^{- 1} (x + 2)^{99} d x

Wende U-Substitution an

= \int_{- 1}^{1} u^{99} d u

Wende die Potenzregel an

= [\frac{u ^{100}}{100}]_{- 1}^{1}

Berechne die Grenzen:

0

= 0

d er i v a t i v e 7 x - \frac{9}{x ^{6}}

t an g e n t f (x) = x e^{- \frac{x}{2}}, at x = \frac{1}{2}

t^{2} y^{^{''}} + 2 t y^{^{'}} - 30 y = 0

x \to 3 lim (\frac{( x + 3 )}{x - 3})

x \to 0 lim (x^{2} ln (x))