x^2y^{''}=y^'+(y^')^2

Lösung

x^{2} y^{^{''}} = y^{^{'}} + (y^{^{'}})^{2}

y = \int \frac{e ^{c_{1}}}{e ^{\frac{1}{x}} - e ^{c_{1}}} d x

Schritte zur Lösung

x^{2} y^{''} (x) = y^{'} (x) + (y^{'} (x))^{2}

Solve using substitution:

y = \int \frac{e ^{c_{1}}}{e ^{\frac{1}{x}} - e ^{c_{1}}} d x

y = \int \frac{e ^{c_{1}}}{e ^{\frac{1}{x}} - e ^{c_{1}}} d x

\frac{\partial}{\partial x} (x^{x y})

\int \frac{1}{x ^{4} - 16} d x

\int_{0}^{1} 5 e^{5 x} d x

\frac{d}{d x} (\frac{9 x}{x})

x \to 0 + lim (x^{x^{8}})