(e^x+y)dx+(e^y+x)dy=0

解答

(e^{x} + y) d x + (e^{y} + x) d y = 0

y = - W (\frac{e ^{\frac{c _{1} - e ^{x}}{x}}}{x}) + \frac{c _{1} - e ^{x}}{x}

求解步骤

(e^{x} + y) d x + (e^{y} + x) d y = 0

求解恰当方程:

y = - W (\frac{e ^{\frac{c _{1} - e ^{x}}{x}}}{x}) + \frac{c _{1} - e ^{x}}{x}

y = - W (\frac{e ^{\frac{c _{1} - e ^{x}}{x}}}{x}) + \frac{c _{1} - e ^{x}}{x}

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