y^{''}+16y=xe^{3x}

Lösung

y^{^{''}} + 16 y = x e^{3 x}

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{e ^{3 x} x}{25} - \frac{6}{625} e^{3 x}

Schritte zur Lösung

y^{''} (x) + 16 y = x e^{3 x}

Solve linear ODE:

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{e ^{3 x} x}{25} - \frac{6}{625} e^{3 x}

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{e ^{3 x} x}{25} - \frac{6}{625} e^{3 x}

x \to 0 lim (9 x + 6)

x \to 0 lim (10 + ∣ x - 5 ∣)

\frac{\partial}{\partial x} (\frac{1}{( x ^{2} + y ^{2} + z ^{2} )})

\frac{d y}{d t} = \frac{3}{t} y + t^{5}

x \to 8 lim (- 6 x)