y^'+2y=18

Lösung

y^{^{'}} + 2 y = 18

y = - e^{- 2 t - c_{1}} + 9

Schritte zur Lösung

y^{'} (t) + 2 y = 18

Solve separable ODE:

y = - e^{- 2 t - c_{1}} + 9

y = - e^{- 2 t - c_{1}} + 9

\int \frac{6 e ^{2 x}}{e ^{2 x} + 10 e ^{x} + 16} d x

t a y l or (1 - x) e^{- x}

in v erse l a pl a ce \frac{1}{( s ^{2} + 9 )}

\int \frac{x ^{4} - 3 x ^{2} + 5}{x ^{4}} d x

x \to - 2 lim (\frac{x + 2}{2 x})